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How Much Iron Is in 98% Ferrous Sulphate Heptahydrate? The 19.7% Fe Calculation

A step-by-step chemical stoichiometry guide explaining how to calculate the 19.7% elemental iron fraction from 98% FeSO₄·7H₂O and avoid dosing errors.

Author: Kiki's Chemical Engineering Team•Published: 2026-10-02•5 min read
Elemental IronStoichiometryChemical CalculationsFerrous SulphateQuality Assurance
How Much Iron Is in 98% Ferrous Sulphate Heptahydrate? The 19.7% Fe Calculation

Crystalline structure of Ferrous Sulphate Heptahydrate (FeSO₄·7H₂O), CAS 7782-63-0.

Quick Answer — How Much Iron Is in 98% Ferrous Sulphate Heptahydrate? The 19.7% Fe Calculation

A 98% minimum specification of Ferrous Sulphate Heptahydrate (FeSO₄·7H₂O) delivers approximately 19.7% elemental iron by weight. The formula weight is 278.01 g/mol and iron contributes 55.845 g/mol, giving a theoretical fraction of 20.087% Fe in 100% pure compound. Multiplying by 98% purity yields 19.685% (rounded to 19.7% Fe).

A stoichiometric derivation and practical calculation protocol determining active elemental iron content in commercial ferrous sulphate grades.

Key Facts

  • •Formula weight of FeSO₄·7H₂O: 278.01 g/mol.
  • •Atomic mass of iron (Fe): 55.845 g/mol.
  • •Theoretical pure crystal iron fraction: 20.087% Fe.
  • •Commercial 98% minimum purity delivers ~19.7% elemental iron.
  • •Never confuse compound purity (98%) with elemental iron concentration.

Primary Use Cases

Calculating dosing rates in wastewater treatment facilities.Formulating elemental iron micronutrients in agricultural fertilizers.Verifying supplier Certificate of Analysis claims against theoretical chemistry.

The Core Stoichiometric Equation

One of the most persistent misunderstandings in chemical procurement is confusing the purity of a chemical compound with the concentration of its constituent elements. When a supplier's Certificate of Analysis declares 'Assay: 98.2% Min', what does this mean for the process engineer who needs to dose 10 mg/L of active iron?

Let us examine the molecular breakdown of Ferrous Sulphate Heptahydrate 98% Min using atomic weights from the periodic table:

  • Iron (Fe): 1 × 55.845 g/mol = 55.845 g/mol
  • Sulfur (S): 1 × 32.065 g/mol = 32.065 g/mol
  • Oxygen in sulfate (O₄): 4 × 15.999 g/mol = 63.996 g/mol
  • Water of crystallization (7H₂O): 7 × 18.015 g/mol = 126.105 g/mol

Summing these components yields the total molar mass of pure FeSO₄·7H₂O:

Molecular Weight = 55.845 + 32.065 + 63.996 + 126.105 = 278.011 g/mol

Calculating the Theoretical Pure Iron Fraction

To determine how much of that total mass is elemental iron:

Iron Fraction = 55.845 / 278.011 = 0.20087 (or 20.087% by weight)

In 100% chemically pure ferrous sulphate heptahydrate, only 20.09% of the weight is iron metal. The remaining 79.91% consists of sulfate ions (SO₄²⁻) and crystal water (7H₂O) integrated into the solid crystalline matrix.

Scaling for 98% Commercial Assay

Commercial technical grades are certified to at least 98.0% FeSO₄·7H₂O purity, with minor allowances for moisture and trace minerals:

Elemental Fe = 20.087% × 0.980 = 19.685% ≈ 19.7% Fe

Therefore, every 25 kg bag of Ferrous Sulphate Heptahydrate 98% contains approximately 4.92 kg of elemental iron (25 kg × 0.19685).

The Risk of Dosing Confusion in Water & Agronomy

If an agronomist prescribes 2 kg of elemental iron per hectare and mistakenly orders 2 kg of ferrous sulphate heptahydrate, the crop will only receive 0.39 kg of iron, failing to correct the chlorosis. Conversely, assuming 98% iron in wastewater leads to under-dosing coagulant by a factor of five. Always base chemical dosing on elemental iron requirements divided by 0.197.

Understand the differences between hydration grades: Ferrous Sulphate Heptahydrate vs Monohydrate.

Avoid costly assay and dosing miscalculations: Common Ferrous Sulphate Buyer Mistakes and How to Avoid Them.

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