How Much Iron Is in 98% Ferrous Sulphate Heptahydrate? The 19.7% Fe Calculation
A step-by-step chemical stoichiometry guide explaining how to calculate the 19.7% elemental iron fraction from 98% FeSO₄·7H₂O and avoid dosing errors.
Crystalline structure of Ferrous Sulphate Heptahydrate (FeSO₄·7H₂O), CAS 7782-63-0.
Quick Answer — How Much Iron Is in 98% Ferrous Sulphate Heptahydrate? The 19.7% Fe Calculation
A 98% minimum specification of Ferrous Sulphate Heptahydrate (FeSO₄·7H₂O) delivers approximately 19.7% elemental iron by weight. The formula weight is 278.01 g/mol and iron contributes 55.845 g/mol, giving a theoretical fraction of 20.087% Fe in 100% pure compound. Multiplying by 98% purity yields 19.685% (rounded to 19.7% Fe).
A stoichiometric derivation and practical calculation protocol determining active elemental iron content in commercial ferrous sulphate grades.
Key Facts
- •Formula weight of FeSO₄·7H₂O: 278.01 g/mol.
- •Atomic mass of iron (Fe): 55.845 g/mol.
- •Theoretical pure crystal iron fraction: 20.087% Fe.
- •Commercial 98% minimum purity delivers ~19.7% elemental iron.
- •Never confuse compound purity (98%) with elemental iron concentration.
Primary Use Cases
The Core Stoichiometric Equation
One of the most persistent misunderstandings in chemical procurement is confusing the purity of a chemical compound with the concentration of its constituent elements. When a supplier's Certificate of Analysis declares 'Assay: 98.2% Min', what does this mean for the process engineer who needs to dose 10 mg/L of active iron?
Let us examine the molecular breakdown of Ferrous Sulphate Heptahydrate 98% Min using atomic weights from the periodic table:
- Iron (Fe): 1 × 55.845 g/mol = 55.845 g/mol
- Sulfur (S): 1 × 32.065 g/mol = 32.065 g/mol
- Oxygen in sulfate (O₄): 4 × 15.999 g/mol = 63.996 g/mol
- Water of crystallization (7H₂O): 7 × 18.015 g/mol = 126.105 g/mol
Summing these components yields the total molar mass of pure FeSO₄·7H₂O:
Molecular Weight = 55.845 + 32.065 + 63.996 + 126.105 = 278.011 g/mol
Calculating the Theoretical Pure Iron Fraction
To determine how much of that total mass is elemental iron:
Iron Fraction = 55.845 / 278.011 = 0.20087 (or 20.087% by weight)
In 100% chemically pure ferrous sulphate heptahydrate, only 20.09% of the weight is iron metal. The remaining 79.91% consists of sulfate ions (SO₄²⁻) and crystal water (7H₂O) integrated into the solid crystalline matrix.
Scaling for 98% Commercial Assay
Commercial technical grades are certified to at least 98.0% FeSO₄·7H₂O purity, with minor allowances for moisture and trace minerals:
Elemental Fe = 20.087% × 0.980 = 19.685% ≈ 19.7% Fe
Therefore, every 25 kg bag of Ferrous Sulphate Heptahydrate 98% contains approximately 4.92 kg of elemental iron (25 kg × 0.19685).
The Risk of Dosing Confusion in Water & Agronomy
If an agronomist prescribes 2 kg of elemental iron per hectare and mistakenly orders 2 kg of ferrous sulphate heptahydrate, the crop will only receive 0.39 kg of iron, failing to correct the chlorosis. Conversely, assuming 98% iron in wastewater leads to under-dosing coagulant by a factor of five. Always base chemical dosing on elemental iron requirements divided by 0.197.
Understand the differences between hydration grades: Ferrous Sulphate Heptahydrate vs Monohydrate.
Avoid costly assay and dosing miscalculations: Common Ferrous Sulphate Buyer Mistakes and How to Avoid Them.
Article Frequently Asked Questions
Related Categories
Chemicals Mentioned in This Guide
Ferrous Sulfate Heptahydrate 98% Min
Ferrous Sulphate Heptahydrate 98% Min (FeSO₄·7H₂O, CAS 7782-63-0) is an industrial-grade iron(II) salt supplied in 25…
CAS 7782-63-0 · Industrial Grade · Crystal
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ABS/LAS (80%) supplied by Kiki's Industrial Chemicals Ltd in 25kg bags across Kenya and East Africa.
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ATMP (50%)
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ATMP 50% for Industrial Use (ATMP)
ATMP (50%) supplied by Kiki's Industrial Chemicals Ltd in 200kg drums across Kenya and East Africa.
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